Quantrex Academy · Free MHT CET PYQ solutions
MHT CET Chemistry Solutions 2026 MHT CET 2026 (19 April Shift 2)

MHT CET Chemistry Question (2026) — Solution

Question

Calculate the solubility of certain gas in solvent with pressure 3 atm at 25^ C (Henry's law constant is 3.0 10^ -2 \, mol dm ^ -3 \, atm ^ -1 )

Options

  1. A. 0.07 M
  2. B. 0.08 M
  3. C. 0.09 M
  4. D. 0.1 M

Answer

C. 0.09 M

Step-by-step solution

According to Henry's law, the solubility of a gas in a liquid is directly proportional to the partial pressure of the gas above the liquid. S = K_H P Given: K_H = 3.0 10^ -2 mol dm ^ -3 atm ^ -1 P = 3 atm Substituting the values: S = (3.0 10^ -2 mol dm ^ -3 atm ^ -1 ) 3 atm S = 9.0 10^ -2 mol dm ^ -3 Since 1 mol dm ^ -3 = 1 M , the solubility is 0.09 M . Answer: 0.09 M

Practice more on Quantrex App →

Related: Chemistry — Solutions · All PYQ Banks