Question
van't Hoff factor for BaCl _2 is 2.47, calculate the percentage dissociation of in its aqueous solution.
MHT CET
Chemistry
Solutions
2026
MHT CET 2026 (19 April Shift 1)
MHT CET Chemistry Question (2026) — Solution
Options
- A. 25.6\%
- B. 35.7\%
- C. 73.5\%
- D. 13.6\%
Answer
C. 73.5\%
Step-by-step solution
The dissociation reaction of BaCl _2 is: BaCl _2 Ba ^ 2+ + 2 Cl ^ - The number of ions produced per formula unit, n = 3. The relation between van't Hoff factor i and degree of dissociation is: i = 1 + (n - 1) Substituting the given values: 2.47 = 1 + (3 - 1) 2.47 = 1 + 2 2 = 1.47 = 0.735 Percentage dissociation = 100 = 73.5\%
Related: Chemistry — Solutions · All PYQ Banks