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MHT CET Chemistry Solutions 2026 MHT CET 2026 (19 April Shift 1)

MHT CET Chemistry Question (2026) — Solution

Question

Which among the following pairs of solutions is isotonic in nature?

Options

  1. A. 0.1 M urea and 0.1 M sucrose
  2. B. 0.1 M urea and 0.1 M KCl
  3. C. 0.1 M sucrose and 0.1 M KCl
  4. D. 0.1 M KCl and 0.1 M CaCl _2

Answer

A. 0.1 M urea and 0.1 M sucrose

Step-by-step solution

Isotonic solutions are those which have the same osmotic pressure at a given temperature. Osmotic pressure is given by = iCRT, where i is the van't Hoff factor, C is the molar concentration, R is the gas constant, and T is the temperature. For two solutions to be isotonic, their effective concentrations must be equal: i_1C_1 = i_2C_2. For 0.1 M urea and 0.1 M sucrose: Urea is a non-electrolyte, so i = 1. Effective concentration = 1 0.1 = 0.1 M. Sucrose is a non-electrolyte, so i = 1. Effective concentration = 1 0.1 = 0.1 M. Since i_1C_1 = i_2C_2, these two solutions are isotonic. For 0.1 M urea and 0.1 M KCl: KCl dissociates into K^+ and Cl^-, so i = 2. Effective concentration = 2 0.1 = 0.2 M. They are not isotonic. For 0.1 M KCl and 0.1 M CaCl _2: CaCl _2 dissociates into Ca^ 2+ and 2Cl^-, so i = 3. Effective concentration = 3 0.1 = 0.3 M. They are not isotonic. Answer: 0.1 M urea and 0.1 M sucrose

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