Calculate the molar mass of nonvolatile solute when 4 g of it is dissolved in 100 g solvent that boils at 319.4 K [K_b = 2.4 K kg mol ^ -1 ; B.P of pure solvent = 319 K]

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Correct answer: C. 240\ gmol ^ -1

Elevation in boiling point is given by T_b = T_b - T_b^0 T_b = 319.4 - 319 = 0.4 K Using the formula for elevation in boiling point: T_b = K_b m = K_b w_2 1000 M_2 w_1 Substituting the given values: 0.4 = 2.4 4 1000 M_2 100 0.4 = 96 M_2 M_2 = 96 0.4 = 240 g mol^ -1 Answer: 240\ gmol ^ -1

MHT CET Chemistry Question (2026) — Solution

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