Calculate van't Hoff factor for aqueous solution of 0.02 m formic acid if it freezes at -0.045 ^ C . [ K_f = 1.86 K kg mol ^ -1 and freezing point of water = 0\ ^ C ]

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Correct answer: A. 1.21

The depression in freezing point is given by T_f = T_f^ - T_f. T_f = 0 - (-0.045) = 0.045 K Using the formula for depression in freezing point: T_f = i K_f m Substituting the given values: 0.045 = i 1.86 0.02 0.045 = i 0.0372 i = 0.045 0.0372 = 1.209 i 1.21 Answer: 1.21

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