Question
18 g of glucose (molar mass = 180 g/mol) is dissolved in water to prepare 500 ml solution at 15^ C . Calculate the osmotic pressure of the solution. [R = 0.0821\ L atm K ^ -1 \ mol ^ -1 ]
MHT CET
Chemistry
Solutions
2026
MHT CET 2026 (16 April Shift 2)
MHT CET Chemistry Question (2026) — Solution
Options
- A. 1.65\ atm
- B. 4.73\ atm
- C. 5.57\ atm
- D. 2.34\ atm
Answer
B. 4.73\ atm
Step-by-step solution
Number of moles of glucose, n = 18 180 = 0.1 mol Volume of solution, V = 500 ml = 0.5 L Temperature, T = 15 + 273 = 288 K Osmotic pressure is given by = CRT = n V RT Substituting the values: = 0.1 0.5 0.0821 288 = 0.2 0.0821 288 = 4.72896 atm 4.73 atm Answer: 4.73\ atm
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