Question
The partial pressure of a gas at 25^ is 0.18 atm, calculate the concentration of the gas dissolved at the same temperature, If K_H is 0.15\ mol dm ^ -3 \ atm ^ -1
MHT CET
Chemistry
Solutions
2026
MHT CET 2026 (11 April Shift 2)
MHT CET Chemistry Question (2026) — Solution
Options
- A. 0.027 M
- B. 1.8 M
- C. 4.5 M
- D. 0.45 M
Answer
A. 0.027 M
Step-by-step solution
According to Henry's law, the concentration of a dissolved gas is directly proportional to its partial pressure. C = K_H P Given: P = 0.18 atm K_H = 0.15 mol dm ^ -3 atm ^ -1 Substituting the values: C = 0.15 0.18 C = 0.027 mol dm ^ -3 Since 1 mol dm ^ -3 = 1 M , the concentration is 0.027 M . Answer: 0.027 M
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