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MHT CET Chemistry Solutions 2026 MHT CET 2026 (11 April Shift 2)

MHT CET Chemistry Question (2026) — Solution

Question

A solution of 50g of solute 'X' is dissolved in 150 g of 'Y' solvent boils at 357.27 K. What is the molar mass of solute? (Given K_b and boiling point pure solvent is 2.77 K kg/mol and 350.06 K respectively.)

Options

  1. A. 132 g/mol
  2. B. 128 g/mol
  3. C. 150 g/mol
  4. D. 15 g/mol

Answer

B. 128 g/mol

Step-by-step solution

The elevation in boiling point is given by T_b = T_b - T_b^0. T_b = 357.27 - 350.06 = 7.21 K. The formula for elevation in boiling point is T_b = K_b W_2 1000 M_2 W_1 . Substituting the given values: 7.21 = 2.77 50 1000 M_2 150 M_2 = 2.77 50 1000 7.21 150 M_2 = 2770 21.63 128 g/mol.

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