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MHT CET Chemistry Solutions 2026 MHT CET 2026 (11 April Shift 1)

MHT CET Chemistry Question (2026) — Solution

Question

Identify from the following pair of solutions that exhibits the same osmotic pressure. [molar mass of urea = 60 g mol^ -1 and molar mass of glucose = 180 g mol^ -1 ]

Options

  1. A. 6 g/L urea solution and 18 g/L glucose solution.
  2. B. 12 g/L urea solution and 18 g/L glucose solution.
  3. C. 18 g/L urea solution and 18 g/L glucose solution.
  4. D. 6 g/L urea solution and 6 g/L glucose solution.

Answer

A. 6 g/L urea solution and 18 g/L glucose solution.

Step-by-step solution

Osmotic pressure is given by = iCRT. For non-electrolytes like urea and glucose, the van't Hoff factor i = 1. For two solutions to exhibit the same osmotic pressure at a given temperature, their molar concentrations must be equal (C_1 = C_2). Molar concentration C = mass per unit volume molar mass . For 6 g/L urea solution: C_ urea = 6 60 = 0.1 mol/L For 18 g/L glucose solution: C_ glucose = 18 180 = 0.1 mol/L Since C_ urea = C_ glucose , these two solutions are isotonic and exhibit the same osmotic pressure. Answer: 6 g/L urea solution and 18 g/L glucose solution.

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