Question
The solubility of N _2 gas in water at 25^ and 1 bar is 6.85 10^ -4 mol L ^ -1 . Calculate the solubility of N _2 gas in water at the same temperature when the partial pressure of N _2 is 0.70 bar
MHT CET
Chemistry
Solutions
2026
MHT CET 2026 (11 April Shift 1)
MHT CET Chemistry Question (2026) — Solution
Options
- A. 5.138 10^ -4 mol L ^ -1
- B. 5.480 10^ -4 mol L ^ -1
- C. 4.795 10^ -4 mol L ^ -1
- D. 4.875 10^ -4 mol L ^ -1
Answer
C. 4.795 10^ -4 mol L ^ -1
Step-by-step solution
According to Henry's law, the solubility of a gas in a liquid is directly proportional to its partial pressure at a constant temperature. S P S_1 P_1 = S_2 P_2 Given S_1 = 6.85 10^ -4 mol L ^ -1 , P_1 = 1 bar , and P_2 = 0.70 bar . S_2 = S_1 P_2 P_1 S_2 = 6.85 10^ -4 0.70 1 S_2 = 4.795 10^ -4 mol L ^ -1 Answer: 4.795 10^ -4 mol L ^ -1
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