Question
How many moles of potassium chlorate are heated to produce 11 2 L oxygen at STP ?
How many moles of potassium chlorate are heated to produce 11 2 L oxygen at STP ?
B. 1 3 mole
The balanced chemical equation for the decomposition of potassium chlorate is: 2KClO_ 3 2KCl + 3O_ 2 At STP, the volume of 1 mole of an ideal gas is 22 4 L. Number of moles of O_ 2 produced is: n(O_ 2 ) = 11 2 22 4 = 1 2 mole From the stoichiometry of the reaction, 3 moles of O_ 2 are produced from 2 moles of KClO_ 3 . Therefore, the number of moles of KClO_ 3 required to produce 1 2 mole of O_ 2 is: n(KClO_ 3 ) = 2 3 n(O_ 2 ) = 2 3 1 2 = 1 3 mole Answer: 1 3 mole
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