Quantrex Academy · Free MHT CET PYQ solutions
MHT CET Chemistry Structure of Atom 2026 MHT CET 2026 (20 April Shift 2)

MHT CET Chemistry Question (2026) — Solution

Question

Identify pair of orbitals having similar (n + l) values from the following.

Options

  1. A. 3s and 3p
  2. B. 2p and 4s
  3. C. 3d and 4p
  4. D. 2p and 3p

Answer

C. 3d and 4p

Step-by-step solution

The (n + l) value for an orbital is calculated by adding the principal quantum number n and the azimuthal quantum number l. For s, p, d, and f subshells, the values of l are 0, 1, 2, and 3 respectively. Calculating (n + l) for the given pairs: For 3s and 3p: (3 + 0) = 3 and (3 + 1) = 4 For 2p and 4s: (2 + 1) = 3 and (4 + 0) = 4 For 3d and 4p: (3 + 2) = 5 and (4 + 1) = 5 For 2p and 3p: (2 + 1) = 3 and (3 + 1) = 4 The pair 3d and 4p has the same (n + l) value of 5. Answer: 3d and 4p

Practice more on Quantrex App →

Related: Chemistry — Structure of Atom · All PYQ Banks