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MHT CET Chemistry Structure of Atom 2026 MHT CET 2026 (19 April Shift 2)

MHT CET Chemistry Question (2026) — Solution

Question

Calculate the shortest wavelength in hydrogen spectrum emission of Lymen series (R_H = 109677\, cm ^ -1 )

Options

  1. A. 9.117 10^ -6 cm
  2. B. 9.241 10^ -6 cm
  3. C. 9.360 10^ -6 cm
  4. D. 9.482 10^ -6 cm

Answer

A. 9.117 10^ -6 cm

Step-by-step solution

For the Lyman series, the transition is from n_2 to n_1 = 1. The shortest wavelength corresponds to the maximum energy transition, which occurs when n_2 = . Using the Rydberg formula: 1 = R_H ( 1 n_1^2 - 1 n_2^2 ) Substituting n_1 = 1 and n_2 = : 1 = R_H ( 1 1^2 - 1 ^2 ) = R_H = 1 R_H Given R_H = 109677 cm ^ -1 : = 1 109677 cm 9.117 10^ -6 cm Answer: 9.117 10^ -6 cm

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