Question
Calculate the shortest wavelength in hydrogen spectrum emission of Lymen series (R_H = 109677\, cm ^ -1 )
Calculate the shortest wavelength in hydrogen spectrum emission of Lymen series (R_H = 109677\, cm ^ -1 )
A. 9.117 10^ -6 cm
For the Lyman series, the transition is from n_2 to n_1 = 1. The shortest wavelength corresponds to the maximum energy transition, which occurs when n_2 = . Using the Rydberg formula: 1 = R_H ( 1 n_1^2 - 1 n_2^2 ) Substituting n_1 = 1 and n_2 = : 1 = R_H ( 1 1^2 - 1 ^2 ) = R_H = 1 R_H Given R_H = 109677 cm ^ -1 : = 1 109677 cm 9.117 10^ -6 cm Answer: 9.117 10^ -6 cm
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