Question
If the velocity of the electron in Bohr's first orbit is 2.19 10^6\ Ms ^ -1 , Calculate the de Broglie wavelength associated with it. [h = 6.626 10^ -34 \ J s & Mass of electrons = 9.10938 10^ -31 kg ]
MHT CET
Chemistry
Structure of Atom
2026
MHT CET 2026 (15 April Shift 2)
MHT CET Chemistry Question (2026) — Solution
Options
- A. 332 pm
- B. 313 pm
- C. 342 pm
- D. 323 pm
Answer
A. 332 pm
Step-by-step solution
The de Broglie wavelength is given by the relation: = h mv Substituting the given values: = 6.626 10^ -34 9.10938 10^ -31 2.19 10^6 = 6.626 10^ -34 19.949 10^ -25 = 0.3321 10^ -9 \ m = 332.1 10^ -12 \ m 332\ pm Answer: 332 pm
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