Calculate the de Broglie wavelength of an electron in the first Bohr orbit of a hydrogen atom if the velocity of an electron in the first orbit is 2.2 10^6 ms ^ -1 . [mass of electron = 9.1 10^ -31 kg, plank's constant (h) = 6.626 10^ -34 J s]
A. 3.31 10^ -10 m
The de Broglie wavelength is given by the relation: = h mv Substituting the given values: = 6.626 10^ -34 9.1 10^ -31 2.2 10^6 = 6.626 10^ -34 20.02 10^ -25 = 0.331 10^ -9 m = 3.31 10^ -10 m Answer: 3.31 10^ -10 m
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