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MHT CET Chemistry Structure of Atom 2026 MHT CET 2026 (13 April Shift 2)

MHT CET Chemistry Question (2026) — Solution

Question

If the energy of an electron in the first Bohr orbit of the H-atom is -2.18 10^ -18 J then the energy of the electron in the second orbit will be

Options

  1. A. -2.18 10^ -18 J
  2. B. -4.36 10^ -18 J
  3. C. -0.545 10^ -18 J
  4. D. -0.273 10^ -18 J

Answer

C. -0.545 10^ -18 J

Step-by-step solution

The energy of an electron in the n-th Bohr orbit of a hydrogen atom is given by E_n = E_1 n^2 . Given E_1 = -2.18 10^ -18 J and n = 2. Substituting the values, we get: E_2 = -2.18 10^ -18 2^2 E_2 = -2.18 10^ -18 4 E_2 = -0.545 10^ -18 J. Answer: -0.545 10^ -18 J

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