Question
Calculate the work done for the following reaction at 27\,^ C C _2 H _ 4(g) + H _ 2(g) C _2 H _ 6(g) (R = 8.314\, JK ^ -1 mol ^ -1 )
MHT CET
Chemistry
Thermodynamics (C)
2026
MHT CET 2026 (19 April Shift 2)
MHT CET Chemistry Question (2026) — Solution
Options
- A. 2494.2 J
- B. 124.71 J
- C. 3741.3 J
- D. 187.07 J
Answer
A. 2494.2 J
Step-by-step solution
The given reaction is C _2 H _ 4(g) + H _ 2(g) C _2 H _ 6(g) Change in number of moles of gaseous species, n_g = n_p - n_r n_g = 1 - (1 + 1) = -1 Work done, W = - n_g RT W = -(-1) 8.314 (27 + 273) W = 1 8.314 300 W = 2494.2 J Answer: 2494.2 J
Related: Chemistry — Thermodynamics (C) · All PYQ Banks