Question
1 mole of an ideal gas is compressed isothermally and reversibly from initial pressure x kPa to final pressure 2x kPa at 300 K. Find the work done (R = 8.314\ J K ^ -1 mol ^ -1 )
MHT CET
Chemistry
Thermodynamics (C)
2026
MHT CET 2026 (18 April Shift 2)
MHT CET Chemistry Question (2026) — Solution
Options
- A. 1432 J
- B. 1865 J
- C. 1296 J
- D. 1729 J
Answer
D. 1729 J
Step-by-step solution
For an isothermal reversible process, the work done is given by: W = nRT ( P_2 P_1 ) Substituting the given values: n = 1 mol T = 300 K P_1 = x kPa P_2 = 2x kPa R = 8.314 J K^ -1 mol^ -1 W = 1 8.314 300 ( 2x x ) W = 2494.2 (2) W = 2494.2 0.693 W 1729 J Answer: 1729 J
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