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MHT CET Chemistry Thermodynamics (C) 2026 MHT CET 2026 (18 April Shift 1)

MHT CET Chemistry Question (2026) — Solution

Question

For a certain reaction, H ^ = 40\ kJ and S ^ = 80\ JK ^ -1 . Find the temperature so that G ^ = 0

Options

  1. A. 500\ K
  2. B. 400\ K
  3. C. 300\ K
  4. D. 600\ K

Answer

A. 500\ K

Step-by-step solution

Using the Gibbs free energy equation: G^ = H^ - T S^ For G^ = 0, we get: T = H^ S^ Given H^ = 40\ kJ = 40000\ J and S^ = 80\ J K ^ -1 . Substituting the values: T = 40000 80 = 500\ K Answer: 500\ K

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