MHT CET Chemistry Question (2026) — Solution

Step-by-step solution

For an isothermal process of an ideal gas, the change in internal energy U = 0. From the first law of thermodynamics: U = q + w q = -w The work done during irreversible compression at a constant external pressure is given by: w = -P_ ext V = -P_ ext (V_2 - V_1) Given: P_ ext = 4 bar V_1 = 25 dm ^3 V_2 = 10 dm ^3 Substituting the values: w = -4 (10 - 25) = 60 bar dm ^3 Since 1 bar dm ^3 = 100 J : w = 60 100 J = 6000 J = 6.0 kJ Therefore, q = -6.0 kJ . The quantity of heat released from the system is 6.0 kJ . Answer: 6 0 kJ