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MHT CET Chemistry Thermodynamics (C) 2026 MHT CET 2026 (16 April Shift 2)

MHT CET Chemistry Question (2026) — Solution

Question

Calculate the enthalpy change when 6 g. CO(g) reacts with sufficient NO _2 (g) according to the following reaction 4\, CO(g) + 2\, NO _2 (g) 4\, CO _2 (g) + 2 N _2 (g) \,;\ _r H^0 = -1200\ kJ

Options

  1. A. -16.08\ kJ .
  2. B. -32.15\ kJ .
  3. C. -64.29\ kJ
  4. D. -128.58\ kJ .

Answer

C. -64.29\ kJ

Step-by-step solution

Molar mass of CO = 12 + 16 = 28\ g mol ^ -1 Number of moles of CO = 6 28 = 3 14 \ mol From the given balanced equation, the enthalpy change for the reaction of 4\ mol of CO is -1200\ kJ . Enthalpy change for 1\ mol of CO = -1200 4 = -300\ kJ Enthalpy change for 3 14 \ mol of CO = -300 3 14 = -64.285\ kJ -64.29\ kJ Answer: -64.29\ kJ

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