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MHT CET Chemistry Thermodynamics (C) 2026 MHT CET 2026 (11 April Shift 2)

MHT CET Chemistry Question (2026) — Solution

Question

The equilibrium constant for a reaction is 100. What will be the value of standard Gibbs energy change at 298 K ? (R = 8.314 J K ^ -1 mol ^ -1 )

Options

  1. A. -11.411 KJ/mol
  2. B. -5.744 KJ/mol
  3. C. -570.584 KJ/mol
  4. D. -57.058 KJ/mol

Answer

A. -11.411 KJ/mol

Step-by-step solution

The standard Gibbs free energy change is given by the equation: G^ = -RT K = -2.303 RT K Substituting the given values: R = 8.314 J K ^ -1 mol ^ -1 T = 298 K K = 100 G^ = -2.303 8.314 298 (100) G^ = -2.303 8.314 298 2 G^ = -11411.7 J mol ^ -1 G^ -11.411 kJ mol ^ -1 Answer: -11.411 KJ/mol

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