The energy, E, of a photon can be expressed as E = hf where f is the frequency and h is Planck's constant. The dimensions of h are the same as that of

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Correct answer: B. angular momentum

E = hf [h] = [E] [f] Substituting the dimensions of energy [E] = [M L^2 T^ -2 ] and frequency [f] = [T^ -1 ]: [h] = [M L^2 T^ -2 ] [T^ -1 ] = [M L^2 T^ -1 ] Dimensions of angular momentum L = mvr are [M][L T^ -1 ][L] = [M L^2 T^ -1 ]. Therefore, the dimensions of Planck's constant are the same as that of angular momentum. Answer: angular momentum

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