NDA General Ability Question (2025) — Solution

Step-by-step solution

During the Summer Solstice in the Northern Hemisphere, the Sun is directly overhead at the Tropic of Cancer (23.5^ N). The angle of elevation of the Sun's rays decreases as the latitudinal distance from the Tropic of Cancer increases. Let us calculate the latitudinal distance of each given option from the Tropic of Cancer: Arctic Circle (66.5^ N): 66.5^ - 23.5^ = 43^ Equator (0^ ): 23.5^ - 0^ = 23.5^ Tropic of Cancer (23.5^ N): 0^ Tropic of Capricorn (23.5^ S): 23.5^ + 23.5^ = 47^ Since the Tropic of Capricorn is at the maximum latitudinal distance from the Tropic of Cancer among the given options, it will experience the most slanted rays, and thus the minimum angle of the Sun's rays. Answer: Tropic of Capricorn