NDA
Mathematics
Application of Derivatives
2025
NDA 2025 (Phase 2)
NDA Mathematics Question (2025) — Solution
Question
Consider the following statements: Statement-I: The function f(x) = x^3 + 128 x has a minimum value 48 at x = 4. Statement-II: As x increases through 4, f'(x) changes sign from positive to negative. Which one of the following is correct in respect of the above statements?
Options
- A. Both Statement-I and Statement-II are correct and Statement-II explains Statement-I
- B. Both Statement-I and Statement-II are correct but Statement-II does not explain Statement-I
- C. Statement-I is correct but Statement-II is not correct
- D. Statement-I is not correct but Statement-II is correct
Answer
C. Statement-I is correct but Statement-II is not correct
Step-by-step solution
Given f(x) = x^3 + 128 x = x^2 + 128 x Differentiating with respect to x, we get: f'(x) = 2x - 128 x^2 = 2(x^3 - 64) x^2 For critical points, f'(x) = 0 x^3 - 64 = 0 x = 4 At x = 4, f(4) = 4^3 + 128 4 = 192 4 = 48 Now, checking the sign of f'(x) around x = 4: For x For x > 4, x^3 > 64 f'(x) > 0 (positive) Since f'(x) changes sign from negative to positive as x increases through 4, x = 4 is a point of local minimum. The minimum value is 48. Thus, Statement-I is correct. Statement-II claims that f'(x) changes sign from positive to negative, which is incorrect. Therefore, Statement-I is correct but Statement-II is not correct. Answer: Statement-I is correct but Statement-II is not correct
Practice more on Quantrex App →
Related: Mathematics — Application of Derivatives · All PYQ Banks