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NDA Mathematics Basic of Mathematics 2026 NDA 2026 (Phase 1)

NDA Mathematics Question (2026) — Solution

Question

If 1- _ 10 2= _ 10 (5^x+4^x+3^x+2^x+1), then what is a value of x ?

Options

  1. A. 10
  2. B. 5
  3. C. 1
  4. D. 0

Answer

D. 0

Step-by-step solution

The given equation is 1 - _ 10 2 = _ 10 (5^x + 4^x + 3^x + 2^x + 1) Simplifying the left hand side: 1 - _ 10 2 = _ 10 10 - _ 10 2 = _ 10 ( 10 2 ) = _ 10 5 Equating this to the right hand side: _ 10 5 = _ 10 (5^x + 4^x + 3^x + 2^x + 1) Since the logarithmic function is one-to-one, we can equate the arguments: 5 = 5^x + 4^x + 3^x + 2^x + 1 5^x + 4^x + 3^x + 2^x = 4 Substituting x = 0 into the equation: 5^0 + 4^0 + 3^0 + 2^0 = 1 + 1 + 1 + 1 = 4 Thus, x = 0 satisfies the equation. Answer: 0

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