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NDA Mathematics Functions 2025 NDA 2025 (Phase 1)

NDA Mathematics Question (2025) — Solution

Question

Consider the following for the two (02) items that follow: A function f is such that f(xy) = f(x+y) for all real values of x and y, and f(5) = 10. What is f(20) + f(-20) equal to?

Options

  1. A. 0
  2. B. 10
  3. C. 20
  4. D. 40

Answer

C. 20

Step-by-step solution

Given f(xy) = f(x+y) for all real values of x and y. Substituting y = 0, we get f(x 0) = f(x + 0), which simplifies to f(0) = f(x) for all real x. This implies that f(x) is a constant function for all real values of x. Since f(5) = 10, the constant value of the function is 10. Thus, f(x) = 10 for all x R . We need to find the value of f(20) + f(-20). f(20) = 10 f(-20) = 10 f(20) + f(-20) = 10 + 10 = 20 Answer: 20

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