Quantrex Academy · Free NDA PYQ solutions
NDA Mathematics Permutation Combination 2025 NDA 2025 (Phase 2)

NDA Mathematics Question (2025) — Solution

Question

How many 4-digit numbers that are divisible by 4 can be formed using the digits 1, 2, 3 and 4 (repetition of digits is not allowed)?

Options

  1. A. 3
  2. B. 6
  3. C. 9
  4. D. 12

Answer

B. 6

Step-by-step solution

A number is divisible by 4 if the number formed by its last two digits is divisible by 4. Using the digits 1, 2, 3, 4 without repetition, the possible two-digit numbers at the end that are divisible by 4 are 12, 24, and 32. For each of these endings, the remaining two digits can be arranged in the first two places in 2! = 2 ways. Total number of such 4-digit numbers is 3 2 = 6. Answer: 6

Practice more on Quantrex App →

Related: Mathematics — Permutation Combination · All PYQ Banks