NDA Mathematics Question (2026) — Solution

Step-by-step solution

Let P(A) 2 = P(B) 3 = P(C) 5 = P(D) 8 = k Then P(A) = 2k, P(B) = 3k, P(C) = 5k, and P(D) = 8k Since A, B, C, and D are mutually exclusive and exhaustive events, P(A) + P(B) + P(C) + P(D) = 1 2k + 3k + 5k + 8k = 1 18k = 1 k = 1 18 We need to evaluate 2P(A) + 3P(B) 4P(C) + 5P(D) Substituting the values in terms of k: 2(2k) + 3(3k) 4(5k) + 5(8k) = 4k + 9k 20k + 40k = 13k 60k = 13 60 Answer: 13 60