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NDA Mathematics Quadratic Equation 2025 NDA 2025 (Phase 2)

NDA Mathematics Question (2025) — Solution

Question

For the following two (02) items: Let and be the roots of the quadratic equation x^2 + ( _ 0.5 (a^2))x + ( _ 0.5 (a^2))^4 = 0, where a^2 1 and _ 0.5 (a^2) > 0. Further, ^2 = ( _ a^2 (0.5)). What is the relation between and ?

Options

  1. A. = 2
  2. B. 2 =
  3. C. = -2
  4. D. 2 = -

Answer

C. = -2

Step-by-step solution

Let p = _ 0.5 (a^2). We are given p > 0. The given quadratic equation is: x^2 + px + p^4 = 0 Let the roots be and . Then: + = -p = p^4 We are given the relation: ^2 = _ a^2 (0.5) Using the change of base formula, _ a^2 (0.5) = 1 _ 0.5 (a^2) = 1 p . Thus, the relation becomes: ^2 = p = p ^2 Substitute = p ^2 into the product of roots: (p ^2)( ) = p^4 p ^3 = p^4 Since p > 0, we can divide by p to get: ^3 = p^3 Assuming is a real root, we have = p. Substitute = p into the sum of roots: + p = -p = -2p Now we can find the relation between and : = -2p = -2 Thus, = -2 . Answer: = -2

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