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NDA Mathematics Quadratic Equation 2025 NDA 2025 (Phase 1)

NDA Mathematics Question (2025) — Solution

Question

If x^2 - x + 1 = 0, then what is (x - 1 x )^2 + (x - 1 x )^4 + (x - 1 x )^8 equal to?

Options

  1. A. 81
  2. B. 85
  3. C. 87
  4. D. 90

Answer

C. 87

Step-by-step solution

Given x^2 - x + 1 = 0 Dividing the entire equation by x, we get: x - 1 + 1 x = 0 x + 1 x = 1 Using the algebraic identity (x - 1 x )^2 = (x + 1 x )^2 - 4 Substituting the value of x + 1 x : (x - 1 x )^2 = (1)^2 - 4 = -3 The given expression is (x - 1 x )^2 + (x - 1 x )^4 + (x - 1 x )^8 This can be written as (x - 1 x )^2 + ( (x - 1 x )^2 )^2 + ( (x - 1 x )^2 )^4 Substituting (x - 1 x )^2 = -3 into the expression: (-3) + (-3)^2 + (-3)^4 = -3 + 9 + 81 = 87 Answer: 87

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