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NDA Mathematics Statistics 2025 NDA 2025 (Phase 1)

NDA Mathematics Question (2025) — Solution

Question

Consider the following for the four (04) items that follow: The frequency distribution of height of students of a class is given below: Height (in cm) Number of Students 160–162 12 162–164 15 164–166 24 166–168 13 What is the median height of the class?

Options

  1. A. 162.41 cm
  2. B. 163.41 cm
  3. C. 164.41 cm
  4. D. 165.41 cm

Answer

C. 164.41 cm

Step-by-step solution

The cumulative frequencies for the given classes are: 160-162: 12 162-164: 12 + 15 = 27 164-166: 27 + 24 = 51 166-168: 51 + 13 = 64 Total number of students, N = 64 N 2 = 64 2 = 32 The cumulative frequency just greater than 32 is 51, which corresponds to the class 164-166. Thus, the median class is 164-166. Lower limit of the median class, L = 164 Cumulative frequency of the class preceding the median class, cf = 27 Frequency of the median class, f = 24 Class width, h = 2 Using the formula for median: Median = L + ( N 2 - cf f ) h Median = 164 + ( 32 - 27 24 ) 2 Median = 164 + ( 5 24 ) 2 Median = 164 + 5 12 Median 164 + 0.416 = 164.41 cm Answer: 164.41 cm

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