NDA
Mathematics
Statistics
2025
NDA 2025 (Phase 1)
NDA Mathematics Question (2025) — Solution
Question
Consider the following for the four (04) items that follow: The frequency distribution of height of students of a class is given below: Height (in cm) Number of Students 160–162 12 162–164 15 164–166 24 166–168 13 What is the median height of the class?
Options
- A. 162.41 cm
- B. 163.41 cm
- C. 164.41 cm
- D. 165.41 cm
Step-by-step solution
The cumulative frequencies for the given classes are: 160-162: 12 162-164: 12 + 15 = 27 164-166: 27 + 24 = 51 166-168: 51 + 13 = 64 Total number of students, N = 64 N 2 = 64 2 = 32 The cumulative frequency just greater than 32 is 51, which corresponds to the class 164-166. Thus, the median class is 164-166. Lower limit of the median class, L = 164 Cumulative frequency of the class preceding the median class, cf = 27 Frequency of the median class, f = 24 Class width, h = 2 Using the formula for median: Median = L + ( N 2 - cf f ) h Median = 164 + ( 32 - 27 24 ) 2 Median = 164 + ( 5 24 ) 2 Median = 164 + 5 12 Median 164 + 0.416 = 164.41 cm Answer: 164.41 cm
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