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NDA Mathematics Statistics 2026 NDA 2026 (Phase 1)

NDA Mathematics Question (2026) — Solution

Question

If the mean of 20 observations, namely x_1,x_2,x_3, ,x_ 20 is 1 414, then what is the value of _ i=1 ^ 20 100(2x_i+4) ?

Options

  1. A. 24168
  2. B. 20828
  3. C. 15248
  4. D. 13656

Answer

D. 13656

Step-by-step solution

Given the mean of 20 observations is 1.414. 1 20 _ i=1 ^ 20 x_i = 1.414 _ i=1 ^ 20 x_i = 20 1.414 = 28.28 We need to find the value of _ i=1 ^ 20 100(2x_i + 4). _ i=1 ^ 20 100(2x_i + 4) = 100 ( 2 _ i=1 ^ 20 x_i + _ i=1 ^ 20 4 ) = 100 ( 2(28.28) + 20 4 ) = 100 (56.56 + 80) = 100 (136.56) = 13656

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