NEET Chemistry Question (2026) — Solution

Step-by-step solution

Let us analyze each reaction to determine the major product: Reaction A: Benzonitrile (C_6H_5CN) is reduced by LiAlH_4, a strong reducing agent, to form benzylamine. C_6H_5CN LiAlH_4 C_6H_5CH_2NH_2 Reaction B: Benzamide (C_6H_5CONH_2) undergoes Hoffmann bromamide degradation in the presence of KOH and Br_2 to form aniline. C_6H_5CONH_2 KOH, Br_2 C_6H_5NH_2 Reaction C: Nitrobenzene (C_6H_5NO_2) is not reduced to aniline by NaBH_4. NaBH_4 is a mild reducing agent and generally does not reduce the -NO_2 group. Reaction D: Acetanilide (C_6H_5NHCOCH_3) undergoes acid-catalyzed hydrolysis upon heating to yield aniline and acetic acid. C_6H_5NHCOCH_3 HCl, H_2O, C_6H_5NH_2 + CH_3COOH Thus, reactions B and D give aniline as the major product. Answer: B and D only