Question
The rate of a reaction quadruples when temperature changes from 27^ C to 57^ C . Calculate the energy o activation. Given R =8.314 ~J ~K ^ -1 ~mol ^ -1 , 4=0.6021
NEET
Chemistry
Chemical Kinetics
2024
NEET 2024
NEET Chemistry Question (2024) — Solution
Options
- A. 380.4 ~kJ / mol
- B. 3.80 ~kJ / mol
- C. 3804 ~kJ / mol
- D. 38.04 ~kJ / mol
Answer
D. 38.04 ~kJ / mol
Step-by-step solution
aligned & ( k _2 k _1 )= E _ a 2.303 R ( 1 ~T _1 - 1 ~T _2 ) \\ & ( 4 1 )= E _ a 2.303 R ( 1 300 - 1 330 ) \\ & E _ a = ( (4)) 2.303 8.314 300 330 30 \\ & =3.804 10^4 ~J / mol \\ & =38.04 ~kJ / mol aligned
Related: Chemistry — Chemical Kinetics · All PYQ Banks