NEET Chemistry Question (2026) — Solution

Step-by-step solution

For a zero-order reaction 2 A B , the rate of reaction is expressed as: Rate = - 1 2 d[ A ] dt = k - d[ A ] dt = 2k Integrating this equation, we get the integrated rate law: [ A ]_0 - [ A ]_t = 2kt Given: Initial concentration, [ A ]_0 = 2 M Rate constant, k = 1.0 mol L^ -1 min^ -1 For 75\% completion of the reaction, the amount of A reacted is: [ A ]_0 - [ A ]_t = 75 100 2 = 1.5 M Substituting these values into the integrated rate equation: 1.5 = 2 1.0 t 2t = 1.5 t = 0.75 min