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NEET Chemistry Chemical Kinetics 2026 NEET 2026 (Re-NEET)

NEET Chemistry Question (2026) — Solution

Question

For an elementary chemical reaction, the Arrhenius plot is given below. If the energy of activation is 6.64 kJ mol^ -1 and R =8.3 J K^ -1 mol^ -1 , the temperature at which the rate constant becomes e^2 min^ -1 , is

Options

  1. A. 250 K
  2. B. 125 K
  3. C. 150 K
  4. D. 200 K

Answer

D. 200 K

Step-by-step solution

According to the Arrhenius equation: k = A - E_a RT For a plot of k versus 1/T, the y-intercept corresponds to A. From the given graph, the line intersects the y-axis at 6. Therefore, A = 6. We are given: E_a = 6.64 kJ mol ^ -1 = 6640 J mol ^ -1 R = 8.3 J K ^ -1 mol ^ -1 k = e^2 min ^ -1 , which gives k = (e^2) = 2 Substituting these values into the Arrhenius equation: 2 = 6 - 6640 8.3 T 6640 8.3 T = 6 - 2 6640 8.3 T = 4 T = 6640 4 8.3 T = 6640 33.2 T = 200 K Answer: 200 K

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