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NEET Chemistry d and f Block Elements 2026 NEET 2026 (Re-NEET)

NEET Chemistry Question (2026) — Solution

Question

The green paramagnetic species formed by heating KMnO_4 at 513 K is

Options

  1. A. KO _2
  2. B. K _2 MnO _4
  3. C. Mn _3 O _4
  4. D. MnO

Answer

B. K _2 MnO _4

Step-by-step solution

When potassium permanganate ( KMnO _4) is heated at 513 K , it decomposes to form potassium manganate, manganese dioxide, and oxygen gas. 2 KMnO _4 513 K K _2 MnO _4 + MnO _2 + O _2 The species K _2 MnO _4 (potassium manganate) is green in color. In K _2 MnO _4, the oxidation state of Mn is +6. The electronic configuration of Mn ^ 6+ is [ Ar ] 3d^1. Since it contains one unpaired electron in the d-orbital, it is paramagnetic in nature. Thus, the green paramagnetic species formed is K _2 MnO _4. Answer: K _2 MnO _4

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