Question
The standard cell potential of the following cell Zn | Zn ^ 2+ ( aq ) | Fe ^ 2+ ( aq ) Fe is 0.32 V . Calculate the standard Gibbs energy change for the reaction : Zn ( s )+ Fe ^ 2+ ( aq ) Zn ^ 2+ ( aq )+ Fe ( s ) (Given : 1 ~F =96487 C )
NEET
Chemistry
Electrochemistry
2024
NEET 2024 (Re-NEET)
NEET Chemistry Question (2024) — Solution
Options
- A. -61.75 ~kJ ~mol ^ -1
- B. +5.006 ~kJ ~mol ^ -1
- C. -5.006 ~kJ ~mol ^ -1
- D. +61.75 ~kJ ~mol ^ -1
Answer
A. -61.75 ~kJ ~mol ^ -1
Step-by-step solution
_r G^ =-n F E_ cell ^ For the given reaction, n=2 _ r G ^ =-2 96487 0.32 =-61751.68 ~J ~mol ^ -1 =-61.751 ~kJ ~mol ^ -1
Related: Chemistry — Electrochemistry · All PYQ Banks