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NEET Chemistry Ionic Equilibrium 2026 NEET 2026 (Re-NEET)

NEET Chemistry Question (2026) — Solution

Question

The correct order of solubility of the given salts in water at 298 K is Salt K_ sp at 298 K AgBr 5.0 10^ -13 Zn(OH)_2 1.0 10^ -15 Hg_2Cl_2 1.3 10^ -18

Options

  1. A. Zn(OH) _2> AgBr > Hg _2 Cl _2
  2. B. Hg _2 Cl _2> Zn(OH) _2> AgBr
  3. C. AgBr > Zn(OH) _2> Hg _2 Cl _2
  4. D. Hg _2 Cl _2> AgBr > Zn(OH) _2

Answer

A. Zn(OH) _2> AgBr > Hg _2 Cl _2

Step-by-step solution

Let s be the solubility of the salt in water. For AgBr : AgBr Ag ^+ + Br ^- K_ sp = s^2 s = 5.0 10^ -13 = 50 10^ -14 7.07 10^ -7 M For Zn(OH) _2: Zn(OH) _2 Zn ^ 2+ + 2 OH ^- K_ sp = s(2s)^2 = 4s^3 s = ( 1.0 10^ -15 4 )^ 1/3 = (250 10^ -18 )^ 1/3 6.3 10^ -6 M For Hg _2 Cl _2: Hg _2 Cl _2 Hg _2^ 2+ + 2 Cl ^- K_ sp = s(2s)^2 = 4s^3 s = ( 1.3 10^ -18 4 )^ 1/3 = (0.325 10^ -18 )^ 1/3 6.87 10^ -7 M Comparing the solubilities: 6.3 10^ -6 > 7.07 10^ -7 > 6.87 10^ -7 Thus, the correct order of solubility is Zn(OH) _2 > AgBr > Hg _2 Cl _2. Answer: Zn(OH) _2> AgBr > Hg _2 Cl _2

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