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NEET Chemistry p Block Elements (Group 15, 16, 17 & 18) 2026 NEET 2026 (Re-NEET)

NEET Chemistry Question (2026) — Solution

Question

Given below are two statements: Statement-I : Heating NaCl with concentrated H_2SO_4 and MnO_2 results in oxidation of Mn. Statement-II : Heating NaI with concentrated H_2SO_4 and MnO_2 results in reduction of Mn. In light of the above statements, choose the most appropriate answer from the options given below:

Options

  1. A. Statement-I is incorrect but Statement-II is correct.
  2. B. Both Statement-I and Statement-II are correct.
  3. C. Both Statement-I and Statement-II are incorrect.
  4. D. Statement-I is correct but Statement-II is incorrect.

Answer

A. Statement-I is incorrect but Statement-II is correct.

Step-by-step solution

The reaction of NaCl with concentrated H _2 SO _4 and MnO _2 is given by: 2 NaCl + MnO _2 + 2 H _2 SO _4 Na _2 SO _4 + MnSO _4 + 2 H _2 O + Cl _2 In this reaction, the oxidation state of Mn changes from +4 in MnO _2 to +2 in MnSO _4. Since the oxidation state decreases, Mn undergoes reduction, not oxidation. Thus, Statement-I is incorrect. The reaction of NaI with concentrated H _2 SO _4 and MnO _2 is given by: 2 NaI + MnO _2 + 2 H _2 SO _4 Na _2 SO _4 + MnSO _4 + 2 H _2 O + I _2 Here, the oxidation state of Mn also changes from +4 to +2, which means Mn undergoes reduction. Thus, Statement-II is correct. Therefore, Statement-I is incorrect but Statement-II is correct. Answer: Statement-I is incorrect but Statement-II is correct.

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