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NEET Chemistry Solutions 2024 NEET 2024 (Re-NEET)

NEET Chemistry Question (2024) — Solution

Question

Mass of glucose ( C _6 H _ 12 O _6 ) required to be dissolved to prepare one litre of its solution which is isotonic with 15 ~g ~L ^ -1 solution of urea ( NH _3 CONH _2 ) is (Given: Molar mass in g mol ^ -1 C : 12, H : 1, O : 16, ~N : 14 )

Options

  1. A. 55 g
  2. B. 15 g
  3. C. 30 g
  4. D. 45 g

Answer

D. 45 g

Step-by-step solution

For isotonic solutions [osmotic pressure must be equal] _1= _2 C _1 RT = C _2 RT C _1= C _2 m 180 1 = 15 60 1 ( ~m is the mass of glucose) m= 180 4 =45 ~g

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