Question
1 gram of sodium hydroxide was treated with 25 mL of 0.75 M HCl solution, the mass of sodium hydroxide left unreacted is equal to
1 gram of sodium hydroxide was treated with 25 mL of 0.75 M HCl solution, the mass of sodium hydroxide left unreacted is equal to
A. 250 mg
aligned & M = W 1000 . M _2 V (in mL ) \\ & W = . M M _2 V (in mL ) 1000 = 0.75 36.5 25 1000 \\ &=0.684 ~g (Mass of HCl ) \\ & 36.5 ~g HCl + 40 ~g NaOH HCl + NaOH aligned 36.5 g HCl reacts with NaOH =40 ~g 0.684 g HCl reacts with NaOH = 40 36.5 0.684 0.750 ~g Amount of NaOH left =1 ~g -0.750 ~g =0.250 ~g =250 mg
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