Question
When 1 dm^3 of CO _2 gas is passed over hot coke, the volume of gaseous mixture after complete reaction at STP becomes 1.4 dm^3. The composition of the gaseous mixture at STP is :
NEET
Chemistry
Some Basic Concepts of Chemistry
2026
NEET 2026 (Cancelled)
NEET Chemistry Question (2026) — Solution
Options
- A. 0.8 dm^3 of CO, 0.8 dm^3 of CO _2
- B. 0.8 dm^3 of CO, 0.6 dm^3 of CO _2
- C. 0.6 dm^3 of CO, 0.8 dm^3 of CO _2
- D. 0.6 dm^3 of CO, 0.4 dm^3 of CO _2
Answer
B. 0.8 dm^3 of CO, 0.6 dm^3 of CO _2
Step-by-step solution
The reaction of carbon dioxide with hot coke is given by: CO _2(g) + C (s) 2 CO (g) Initial volume of CO _2 = 1 dm^3 Let x dm^3 of CO _2 react with hot coke. Volume of CO _2 remaining = 1 - x dm^3 Volume of CO formed = 2x dm^3 Total volume of the gaseous mixture = (1 - x) + 2x = 1 + x dm^3 Given that the total volume after the reaction is 1.4 dm^3: 1 + x = 1.4 x = 0.4 dm^3 Volume of CO _2 remaining = 1 - 0.4 = 0.6 dm^3 Volume of CO formed = 2 0.4 = 0.8 dm^3 The composition of the gaseous mixture is 0.8 dm^3 of CO and 0.6 dm^3 of CO _2. Answer: 0.8 dm^3 of CO, 0.6 dm^3 of CO _2
Related: Chemistry — Some Basic Concepts of Chemistry · All PYQ Banks