Question
The amount of carbon dioxide evolved upon complete combustion of 116 g of n-butane is (Given: atomic mass in amu H =1, C =12 and O =16)
NEET
Chemistry
Some Basic Concepts of Chemistry
2026
NEET 2026 (Re-NEET)
NEET Chemistry Question (2026) — Solution
Options
- A. 362 g
- B. 352 g
- C. 322 g
- D. 176 g
Answer
B. 352 g
Step-by-step solution
The balanced chemical equation for the combustion of n-butane is: C_4H_ 10 + 13 2 O_2 4CO_2 + 5H_2O Molar mass of n-butane (C_4H_ 10 ) = 4 12 + 10 1 = 58 g/mol Number of moles of n-butane = 116 58 = 2 moles From the balanced equation, 1 mole of n-butane produces 4 moles of CO_2. Number of moles of CO_2 produced = 2 4 = 8 moles Molar mass of CO_2 = 12 + 2 16 = 44 g/mol Mass of CO_2 produced = 8 44 = 352 g Answer: 352 g
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