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NEET Chemistry Thermodynamics (C) 2024 NEET 2024 (Re-NEET)

NEET Chemistry Question (2024) — Solution

Question

For the following reaction at 300 K A _2( ~g )+3 ~B _2( ~g ) 2 AB _3( ~g ) the enthalpy change is +15 kJ then the internal energy change is:

Options

  1. A. 19988.4 ~J
  2. B. 200 J
  3. C. 1999 J
  4. D. 1.9988 kJ

Answer

A. 19988.4 ~J

Step-by-step solution

A _2( ~g )+3 ~B _2( ~g ) 2 AB _3( ~g ) n_ ( g ) = n _ ( P ) - n _ ( R ) =2-3-1=-2 H= U+ n_g R T 15 1000= U-2 8.314 300 U=15000+600 8.314 =15000+6 831.4 =15000+4988.4 U=19988.4 ~J

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