Question
A 10 F capacitor is connected to a 210 ~V , 50 ~Hz source as shown in figure. The peak current in the circuit is nearly ( =3.14) :
NEET
Physics
Alternating Current
2024
NEET 2024
NEET Physics Question (2024) — Solution
Options
- A. 0.93 A
- B. 1.20 A
- C. 0.35 ~A
- D. 0.58 A
Answer
A. 0.93 A
Step-by-step solution
Capacitive Reactance aligned X_C & = 1 C = 1 2 f C = 1 2 3.14 50 10 10^ -6 \\ & = 1000 3.14 aligned aligned & V_ rms =210 ~V \\ & i_ rms = V_ rms X_C = 210 X_C aligned aligned Peak current & = 2 i_ ms = 2 210 1000 3.14=0.932 \\ & 0.93 ~A aligned
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