Question
An ac voltage V=220 (2 10^3 t) Volt is applied to a series LCR circuit. Then the current amplitude in this circuit is : (Given : L=10 mH, C=25\, , R=100\, )
NEET
Physics
Alternating Current
2026
NEET 2026 (Re-NEET)
NEET Physics Question (2026) — Solution
Options
- A. 22.0 A
- B. 2.2 A
- C. 5.5 A
- D. 11.0 A
Answer
B. 2.2 A
Step-by-step solution
Given V = 220 (2 10^3 t) V, the peak voltage is V_m = 220 V and the angular frequency is = 2 10^3 rad/s. The inductive reactance is X_L = L = (2 10^3) (10 10^ -3 ) = 20 \, . The capacitive reactance is X_C = 1 C = 1 (2 10^3) (25 10^ -6 ) = 1 50 10^ -3 = 20 \, . Since X_L = X_C, the circuit is in resonance. The impedance of the circuit is Z = R^2 + (X_L - X_C)^2 = R = 100 \, . The current amplitude is I_m = V_m Z = 220 100 = 2.2 A. Answer: 2.2 A
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