A wire of length ' 1 and resistance 100 is divided into 10 equal parts. The first 5 parts are connected in series while the next 5 parts are connected in parallel. The two combinations are again connected in series. The resistance of this final combination is:

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Correct answer: A. 52

Divided into 10 parts aligned R & = l A \ R^ & = l 10 A = R 10 \ R_S & =5 R 10 [series] \ R_S & =50 \ R_P & = R 50 [parallel] \ R_ eq & =R_S+R_P \ & =52 aligned

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