A galvanometer of resistance 100\ gives full scale deflection for a current of 1 mA. It is converted into an ammeter of range 0 - 10 A. The shunt required is :

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Correct answer: A. 0.01\

Given G = 100\ , I_g = 1 mA = 10^ -3 A , and I = 10 A . The shunt resistance S required to convert a galvanometer into an ammeter is given by: S = I_g G I - I_g Substituting the values: S = 10^ -3 100 10 - 10^ -3 Since 10 10^ -3 , we can approximate 10 - 10^ -3 10. S 0.1 10 = 0.01\ Answer: 0.01\

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